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PSEB Math Paper Set 1 2015

PSEB Class-X
Mathematics paper 2015  Set-A

Time allowed: Three Hours                                                    Maximum marks-50

1)      If  =  =   then what will be the solution of pair of linear equation?   1
a)      Write the common difference of Arithmetic progression 3,1,-1,-3…... 1
b)`     Fill in the blanks(?) if DADE~DABC then =                                      1
c)       What is the value of  ?                                                                       1
d)      Write the formula to find the volume of cuboid?                                   1
2)      Find the HCF and LCM of 15,12 and 21 using the factorization method.  2
3)      Divide 2x2+7x-1 by x+4.                                                                        2
4)      Find the roots of quadratic equation 6x2-x-2=0                                     2
5)      Which term of the A.P.: 2,7,12,17…….is 77?                                      2
                                                Or
          Find the sum of first 22 terms of the A.P.: 9,4,-1,….
6)      ABC is an isosceles triangle , right angled at C. Prove  that AB2=2AC2.  2
                                                Or
  Prove that the tangents drawn at the ends of a diameter PQ of a circle are parallel.                                                                                                          2
7)      Draw a  line segment of length 7.4 cm and divide it in the ratio 5:8.     2
                                                     Or
 Construct a triangle similar to a given triangle XYZ with its side equal to  of the corresponding sides of the triangle XYZ.                                                  2           
8)      A box contains 5 red marbles,8 white marbles and 4 green marbles.One marble is taken out of the box at random. What is the probability that the marble  taken out will be
i)       red?
ii)      white?
iii)     not green?                                                                                             2
9)      Find all possible solutions of the following pair of linear equations:
          5x+6y=16   and 2x-2y=2                                                                      3
10)    A ladder 5 m long reaches a  window 4 m above the ground .Find the distance of the foot of the ladder from the base of the wall.                              3
11)    If  A(-4,-5),B(-1,-6),C(4,5) and D(-5,7) are the vertices of a  quadrilateral ABCD, then find the area of the quadrilateral.                                                3
                                                          Or
Find the coordinates of the point which divides the join of the  line segment of the points(-3,5) and (2,-5) in the ratio 2:3.                                                                     3
12)    Prove that  =                                                                       3
13)    An observer 1.5 m tall away from the chimney. The angle of elevation of the top of chimney from eyes is 45.Find the height of the chimney.                    3
14)    From each corner of a square of side 12 cm a quadrant of a circle of radius 3 cm is cut and also a circle of diameter 6 cm is cut as shown in the adjacent fig. Find the area of remaining portion of the square.                                            3
                                     
                                                         
15)    The table below shows the daily expenditure on food of 25 households in a locality.                                                                                        
Daily expenditure
100-150
150-200
200-250
250-300
300-350
Number of households
4
5
12
2
3
Find the mean daily expenditure on food by a suitable method.                     3
                                                           Or
The distribution below gives the weight of 30 students of a class. Find the median weight of the students.                                                                                         3
Weight(in Kg)
45-50
50-55
55-60
60-65
65-70
70-75
75-80
Number of Students
2
3
8
6
6
3
2

16)    Prove that in a triangle, if the square of one side is equal to the sum of the squares of the other two sides, then the opposite the first side is a right angle  5
                                                 Or
Two tangents AB and AC are drawn to a circle with centre O from the external point A .Prove thatÐBAC=2ÐOBC                                                                         5
17)    A metallic sphere of radius 2.1 cm is melted and recast into the shape of a cylinder of radius 3 cm. Find the height of the cylinder.                                      5
                                                          Or
A drinking glass is in the shape of a frustum of a cone of height 14 cm.The diameters of two circular ends are 36 cm and 30 cm.Find the capacity of the glass.5
                                                                                                                            
                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                            


  
           




Formule for 10th Class









FORMULAE Algebra

FORMULAE
Algebra

1. (a + b)2 = a2 + b2 + 2ab = (a - b) 2 + 4ab
2. (a- b) 2 = a2 + b2 - 2ab = (a + b) 2 – 4ab
3. a2- b2 = (a - b) (a + b)
4. a2 + b2 = (a + b)- 2ab = (a - b) 2 + 2ab
5. (a + b) 2 + (a- b) 2 = 2(a2 + b2)
6. (a + b) 2 – (a - b) 2 = 4ab
7. (a + b + c) 2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
8. a2 + b2 + c2 - ab - bc - ca =1/2[(a-b) 2 + (b -c) 2 + (c- a) 2]
9. (a + b)3 = a3 + b3 + 3ab (a + b) = a3 + 3a2b + 3ab2 + b3
10. (a- b) 3 = a3 - b3 -3ab (a -b) = a3 - 3a2b + 3ab2 - b3
11. a3 + b3 = (a + b) 3 - 3ab (a + b) = (a + b) (a2–- ab + b2)
12. a3 - b3= (a - b) 3 + 3ab (a- b) = (a- b) (a2 + ab + b2)
13. (a + b + c) 3 = a3 + b3 + c3 + 3(a + b) (b + c) (c + a)
14. a3 + b3 + c3 – 3abc = (a + b + c) (a2 + b2 + c2 - ab - bc - ca)

If a + b + c = 0 then a3 + b3+ c3 = 3abc

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